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4 years ago

Solve this system of equations:

Mathematics

1 answer:

kobusy [5.1K]4 years ago

8 0

X=2, y=3
I believe the answer is D..
Hope this helps! :)

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What is the quotient of 1 and 2/3 divided by 4/5

shtirl [24]

Answer:

2 and 1/12

Step-by-step explanation:

1 and 2/3 = 5/3.

when dividing fractions, invert and multiply.

5/3x5/4=25/12

=2 and 1/12

3 0

3 years ago

Read 2 more answers

Is a triangle with the given side lengths of 15cm, 17cm, and 19cm a right triangle?

Alexandra [31]

Lets see!
We need to use the pythagorean theorem (a^2+b^2=c^2) to check.
So..
15^2+ 17^2 = 19^2
225+ 289= 361
Hm 225 and 289 do NOT equal 361 therefore it is NOT a right triangle.

3 0

3 years ago

Read 2 more answers

On Monday your bank account balance was -$12.58. Because you didn't realize this you wrote a $30.72 check. A. What is the new ba

Liula [17]

A-
-$12.58
B-
-$37.58
C-
You need $37.58 to bring it back up to $0

8 0

4 years ago

Find the y-intercept for the parabola defined by the equation y=x^2-x-12

o-na [289]

Answer:

The y-intercept is (0,-12).

Step-by-step explanation:

Given equation is $y=x^2-x-12$ .

Now question says to find the y-intercept of the given parabola $y=x^2-x-12$ .

We know that y-intercept means the y-value when x-value equals 0

so let's plug x=0 into given equation $y=x^2-x-12$ then solve that for y.

$y=x^2-x-12$

$y=0^2-0-12$

$y=0-0-12$

$y=-12$

Hence the y-intercept is (0,-12).

6 0

3 years ago

a town has 2 fire engines operating independently . the probability that a specific engine is available when needed is 0.96. wha

tester [92]

Answer:

The probability that neither is available when needed

$P(A n B)^{c} = 0.04$

Step-by-step explanation:

A town has 2 fire engines operating independently

Given data the probability that a specific engine is available when needed is 0.96.

Let A and B are the two events of two fire engines

given P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)

Independent events : P( A n B) = P(A) P(B)

The probability that neither is available when needed

$P(A n B)^{c} = 1- P(A n B)$

$P(A n B)^{c} = 1- 0.96 = 0.04$

7 0

4 years ago