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Alekssandra [29.7K]
3 years ago
12

Please please answer will give brainliest

Mathematics
2 answers:
Paraphin [41]3 years ago
6 0

Answer:

D. (Jesse with a score of 75)

Step-by-step explanation:

Abby has 15/20 on her quiz, and we can convert that to 0.75. We can turn 0.75 into 75 points in her quiz.

Jesse has 18/30 on her quiz, and we can convert that to 0.60. We can turn 0.60 into 60 points in her quiz.

0.75 > 0.60, so Jesse has more.

exis [7]3 years ago
6 0

Answer:

Jesse has the better score

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Tell your cousin good luck and that the answer is 5 :)
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Which of the following equations has no solutions?
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May. Be D



Am I right
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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit  10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is \overline A=\textrm{Missing a target at least once}

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, P(A)=0.95^{10}=0.5987

We know that the sum of probability of an event and its complement is 1.

So, P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0
3 years ago
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Pls help 25h²- 16t² factorise it​
noname [10]

Answer:

(5h-4t)(5h+4t)

Step-by-step explanation:

25h² - 16t²

adding  and subtracting 20ht from it        (√25 and √16 = 5x4 = 20):

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8 0
3 years ago
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Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
3 years ago
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