Solve for k 8k-2z=16

Please solve this question!!

GaryK [48]

Answer: (i) 1/221 (ii) 11/221 (iii) 95/663 (iv) 1/663

Step-by-step explanation:

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards → 3/51 = 1/17

1st Draw 2nd Draw Outcome Probability

King: P(K) = 1/13 King: P(K₂/K₁) = 1/17 King, King (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards → 11/51

1st Draw 2nd Draw Outcome Probability

Face: P(F) = 3/13 Face: P(F₂/F₁) = 11/51 Face,Face (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards → 19/51

1st Draw 2nd Draw Outcome Probability

Black: P(B~) = 5/13 Black: P(B~₂/B~₁) = 19/51 B~,B~ (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards → 1/51

1st Draw 2nd Draw Outcome Probability

Ace: P(A) = 1/13 Qh: P(Qh₂/A₁) = 1/51 Ace,Queen(h) (1/13) x (1/51) = 1/663

7 0

3 years ago

Find the endpoint:

scZoUnD [109]

Answer:

The coordinates of Point D are: (-5,-8)

Step-by-step explanation:

The formula for mid-point is given by:

$M = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})$

For the point (x1,y1) and (x2,y2)

Given that

M = (-3, -6)

C = (-1, -4) => (x1,y1)

Putting the values of given points in the formula for mid-point

$(-3,-6) = (\frac{-1+x_2}{2} , \frac{-4+y_2}{2})$

Putting respective coordinates equal

$-3 = \frac{-1+x_2}{2}\\-6 =-1+x_2\\x_2=-6+1\\x_2 = -5\\AND\\-6 = \frac{-4+y_2}{2}\\-12 = -4+y_2\\y_2 = -12+4\\y_2 = -8$

Hence,

The coordinates of Point D are: (-5,-8)

3 0

2 years ago

(3,y) (1,4) m= -2 what is the value of y if the line through the two given points is to have indicated slope

riadik2000 [5.3K]

Answer:

y=0

Step-by-step explanation:

The equation for the slope is

m = ( y2-y1)/(x2-x1)

-2 = (4-y)/(1-3)

-2 = (4-y)/-2

Multiply each side by -2

4 = 4-y

Subtract 4 from each side

4-4 = 4-y-4

0 = -y

0=y

5 0

2 years ago

Find the differential coefficient of <img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

2 years ago

Factor the trinomial x^2 - 16x +63

Butoxors [25]

Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer: (x - 7) (x - 9)

3 0

3 years ago

Solve for k8k-2z=16​

Solve for k8k-2z=16