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Troyanec [42]
3 years ago
13

Find all 6 trig functions given the terminal side goes through point (0,-3)

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0
So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall  sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

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Answer:

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Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

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Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

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Independent Practice
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Answer: THE ANSWER IS D. (-27, -7, -2, 8, 48)

Step-by-step explanation:

Graph.

y = 5 x − 2

{ − 5 ,  − 1 ,  0 ,  2 ,  10 }

The chosen topic is not meant for use with this type of problem. Try the examples below.

1  ,  2  ,  2  ,  2  ,  3  ,  4  ,  4  ,  5  ,  8  ,  9  ,  10

11  ,  14  ,  14  ,  17  ,  17  ,  17  ,  41  ,  44  ,  47  ,  71  ,  74  ,  77

12  ,  15  ,  45  ,  65  ,  78

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