There not the same
vectors have magnitude and direction scalars on the other hand only have magnitude
Answer: 0, 1, -3
Step-by-step explanation:
f(x) = x^3 +2x^2 -3x
f(x) = x(x^2 +2x-3)
f(x) = x(x-1)(x+3)
to find zeroes, plug into f(x) and solve for each value of x. doing this gives 0, 1, and -3
Answer:
<u>(7,a) Where a ∈ R - {7}</u>
<u>OR</u>
<u>(-2,a) where a ∈ R - {-2}</u>
Step-by-step explanation:
The coordinates of the given line from the right to the left are:
(7,1) and (-2,1)
So, to make a right triangle, we need to make a right angle or by another words, we need to a make a perpendicular line to the given line (i.e: a vertical line parallel to the y-axis at one of the given points)
So, the third vertex must be on the line x=7 or x=-2
So, the coordinates of the third vertex is:
<u>(7,a) Where a ∈ R - {7}</u>
<u>OR</u>
<u>(-2,a) where a ∈ R - {-2}</u>
Answer: y = 4x/3 - 5/2
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
c represents the y intercept
m = slope = (y2 - y1)/(x2 - x1)
The given line, L1 passes through A(6, - 7) and B(- 6, 2). The slope of line L1 is
m = (2 - - 7)/(- 6 - 6) = 9/ -12 = - 3/4
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.
Therefore, the slope of line L2 passing through the midpoint, M is 4/3
The formula determining the midpoint of a line is expressed as
[(x1 + x2)/2 , (y1 + y2)/2]
Midpoint, M = [(6 + -6)/2 , (- 7 + 2)/2]
= (0, - 5/2]
This means that the y intercept of line L2 is - 5/2
The equation of L2 becomes
y = 4x/3 - 5/2
