Answer:
The minimum score required for an interview is 73.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If test scores are normally distributed, what is the minimum score required for an interview?
Top 25%, which is at least the 100-25 = 75th percentile, which is the value of X when Z has a pvalue of 0.75. So it is X when Z = 0.675.
The minimum score required for an interview is 73.4.
3 x 3 x 3 x 3 = 243
-3 x -3 x -3 x -3 x -3 x -3 x -3 x -3 x -3 = -19683
243 x -19683 = -4782969
its sounds a little off... but that should be your answer if you typed the question in right..
I hope this helped.
Answer:
idk
Step-by-step explanation:
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