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WINSTONCH [101]
3 years ago
12

Help please I’m being timed!!

Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer:d

Step-by-step explanation:

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It will take him 50 minutes to complete the painting.

Step-by-step explanation:

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The area of Taylor Square bedroom is 256 feet what is the length of any side wall in his bedroom
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64 ft for each wall in his bedroom.
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Read 2 more answers
Two sides of a triangle are equal in length and double the length of the shortest side. The perimeter of the triangle is 36 inch
Lostsunrise [7]
To solve this, you can set up an equation. Make the length of the shortest side x, so the 2 sides double the length will equal 2x. Since they all equal the perimeter of 36, do x + 2x + 2x =36. These values all represent the sides(2 longer, one short). Combine like terms to get 5x=36 then divide by 5 to find the value of x. x=7.2in meaning the shorter side is 7.2 inches while the longer sides are both 14.4 inches each since they are double in size.
3 0
4 years ago
Nathan boards an elevator in the lobby that is headed up at 160 meters per minute. Meanwhile, 210 meters above, Joey boards an a
Vesna [10]

Let time be t , distance be d

  • 160t=d-(1)
  • 230t=210-d-(2)

Put value in eq(2)

\\ \rm\longmapsto 230t=210-(160t)

\\ \rm\longmapsto 70t=210

\\ \rm\longmapsto t=30min

8 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
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