Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
1. 56 : 35 = 1.6
2. 1.6* 100 = 160
3. The answer is 160
Answer:
yes
Step-by-step explanation:
Use Pythagorean Theorem:
10² + 49.5² = 50.5² ??
100 + 2450.25 = 2550.25
2550.25 = 2500.25