Answer:
Step-by-step explanation:
Let
Original price = p
Less Discount = 20%
Total discount paid for the item = 20% of p
= 20/100 * p
= 0.2 * p
= 0.2p
Actual price after discount = 100% - 20%
= 80%
Total price paid for the item = 80% of p
= 80/100 * p
= 0.8 * p
= 0.8p
Answer: y= 2x-8
Step-by-step explanation:
2y-4x=-16
2y=-16+4x
y=-8+2x
y= 2x-8
Answer:
Depends on which answer they give you to answer. If you have the one I have which is *IRA contribution* then go for it!
Answer:
Step-by-step explanation:
Solutions, zeros, and roots of a polynomial are all the same exact thing and can be used interchangeably. When you factor a polynomial, you solve for x which are the solutions of the polynomial. Since, when you factor a polynomial, you do so by setting the polynomial equal to 0, by definition of x-intercept, you are finding the zeros (don't forget that x-intercepts exist where y is equal to 0). There's the correlation between zeros and solutions.
Since factoring and distributing "undo" each other (or are opposites), if you factor to find the zeros, you can distribute them back out to get back to the polynomial you started with. Each zero or solution is the x value when y = 0. For example, if a solution to a polynomial is x = 3, since that is a zero of the polynomial, we can set that statement equal to 0: x - 3 = 0. What we have then is a binomial factor of the polynomial in the form (x - 3). These binomial factors found from the solutions/zeros of the polynomial FOIL out to give you back the polynomial equation.
Answer:
![The \ area \ of \ the \ figure = 4\dfrac{1}{2} \cdot \pi + 18 \ cm^2](https://tex.z-dn.net/?f=The%20%5C%20area%20%5C%20of%20%5C%20the%20%5C%20figure%20%3D%204%5Cdfrac%7B1%7D%7B2%7D%20%5Ccdot%20%5Cpi%20%2B%2018%20%5C%20cm%5E2)
Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² =
.