Question

What is the equation of the line that passes through the points (-1, -2) and

Answer 1

Given

• (-1 , -2)
• (3 ,10)

First calculating slope

Slope(m) = (y2 -y1) / (x2 - x1)

= ( 10+ 2)/ ( 3 + 1)

= 12 / 4

= 3

Now The equation of line is

y - y1 = m ( x - x1)

y +2 = 3 ( x +1)

y+2 = 3x + 3

y = 3x + 3 -2

y = 3x + 1

Answer 2

Step-by-step explanation:

Given points (-1 , -2) and (3 ,10)

First calculating slope

Slope(m) = (y2 -y1) / (x2 - x1)

= ( 10+ 2)/ ( 3 + 1)

= 12 / 4

= 3

Now The equation of line is

y - y1 = m ( x - x1)

y +2 = 3 ( x +1)

y+2 = 3x + 3

y = 3x + 3 -2

y = 3x + 1