If you're solving for p, it would look like this: p = q/2 - 2.5r.
They sold 17 rolls. If 45 were sold at $4 dollars then $4×45= 180 If they made 265 dollars so you have to subtract 180$265-180= 85 dollarsYou know the remainder were sold at $5 dollar and dividing 85÷5= 17
Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.
5/4 would be ur answer point slip formula is y^2 - y^1 over x^2 - x^1
Answer:
Nine
Step-by-step explanation:
3 dollars for children tickets : x
5 dollars for adult tickets: y
Equation is:
3x+5y=57
Where 57 is the total amount spent
x+y=15
where 15 is the total number of tickets bought
3x+5y=57
5(x+y)=5(15)
___________________
3x+5y=57
5x+5y=75
minus the equations top to bottom=
-2x= -18
x= -18/(-2)
x=9
He bought a total of 9 children tickets