Ask question

Ask question

All categories

ICE Princess25 [194]

3 years ago

6

stephanies solves math equations at a constant rate of 2/3 equation per minute. which graph best represents y the total number o

f equations stephanie solved in x minutes

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

F

Step-by-step explanation:

The slope is 2/3. That means you go up two units and right 3 units. The only graph that does tat is F.

You might be interested in

PLEASE HELP! WILL REWARD BRAINLIEST TO BEST ANSWER WRITE DOWN INFORMATION. Create all four digit numbers that are divisible by 8

AnnZ [28]

Answer:

Example: 25,216 - the last 2 digits are 16 which is a multiple of 4 so this number is divisible by 4. Using the digits 1, 2, 3, 4, 5 only once, there are only a four combinations that create numbers divisible by 4…..12, 24, 32, 52.

Step-by-step explanation:

7 0

3 years ago

SOMEONE JUST ANSWER THIS FOR BRAINLIEST PLEASE!!

Lana71 [14]

you would factor using the perfect square method to get

(3m+5n)^2

4 0

4 years ago

Read 2 more answers

The value of 7 + 4 · 5 is 27. True False

Afina-wow [57]

7 + 4 x 5
7 + 20
27
True

7 0

4 years ago

HELP please this is a TEST!!

stealth61 [152]

The answer is y=-3/2x +3 so D

8 0

3 years ago

Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?

Natasha_Volkova [10]

Answer:

$24567389+35432611 =60000000$

Step-by-step explanation:

Given

$24567389+35432611 =$

Required

Solve

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

<em>The numbers in parentheses are carried from previous sum</em>

Start from the right

$9 + 1 = 10 \to$ Write 0, carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0

$8 + 1 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0

$7+2 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0

$5 +4 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0

$4 +5 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0 0

$2 +3 + (1) = 6 \to$ Write 6

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

6 0 0 0 0 0 0 0

Hence:

$24567389+35432611 =6 0 0 0 0 0 0 0$

8 0

3 years ago