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3 years ago

A fish tank is in the shape of a cube. Its volume is 125ft3. What is tge area of one face of the tank?

Mathematics

1 answer:

kenny6666 [7]3 years ago

8 0

Answer:

this is your answer

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If there are 120 calories in 4 ounces of hot fudge, how many calories are in 8

miss Akunina [59]

Answer:

240 calories

Step-by-step explanation

You're doubling the amount of fudge, so double the amount of calories. You could also think of it as 2 4-oz portions of fudge, then just add the calories (120+120) together.

3 0

3 years ago

10. Find the value of the function () = 15x2 - 4 if x = 6.

nikdorinn [45]

Answer:

your question is not clear

Step-by-step explanation:

because of option not correct arrange

5 0

3 years ago

A plumber charges a flat fee of $76 to visit a home and examine a clogged drain. The plumber charges an additional $24 per hour

prisoha [69]

Answer:

(a) 12 hours

(b) $220

Step-by-step explanation:

(a) First we plug in $364 for C

C=76+24h

364=76+24h

Subtract 76 from both sides

24h=288

Divide both sides by 24

h=12

She spent 12 hours fixing the drain

(b) First we plug 6 hours in for h

C=76+24(6)

Multiply it out

C=76+144

Add

C=220

It costs $220 for fixing a drain that takes 6 hours

5 0

2 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

Find the slope of the line that passes through (9, 8) and (4, 6).

andreev551 [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers