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ANTONII [103]
3 years ago
15

Solving systems of equations algebraically.

Mathematics
1 answer:
Elanso [62]3 years ago
8 0

Answer:

x = 2

y = -1

Step-by-step explanation:

Since it gives you the value of y already, just plug that into the equation, like so:

y = 4x - 9

x - 3 = 4x - 9

<em><u>Subtract the x from both sides:</u></em>

x - 3 = 4x - 9

-x       - x

__________

-3 = 3x - 9

<em><u>Then, add 9 to both sides:</u></em>

-3 = 3x - 9

+9        + 9

________

6 = 3x

<em><u>Divide both sides by 3:</u></em>

2 = x

<em><u>Now plug in x for y:</u></em>

y = x - 3

y = 2 - 3

y = -1

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kotykmax [81]
When multiplying out you get:

x2+4x-3x-12....

so you'd be adding the +4x to the -3x

x2 + x - 12
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3 years ago
The authors of a paper titled "Age and Violent Content Labels Make Video Games Forbidden Fruits for Youth" carried out an experi
o-na [289]

Answer:

T = 290

Step-by-step explanation:

We can find the sum of all observations multiplying sample size (n) by sample mean (x).

Sum of all observations in the data set is,

T=n_{1} x_{1}+n_{2}x_{2}+n_{3}x_{3}+n_{4}x_{4}\\T=10(5.3)+10(7)+10(8.5)+10(8.2)\\T=53+70+85+82\\T=290

Hope this helps!

7 0
3 years ago
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Aliun [14]
《ANSWER》

《LINEAR EQUATIONS》

Solving all we get as

↪1) 5 (x -2) = 5x - 7

since after solving X is cancelled , NO SOLUTION

↪2) -3 (x - 4) = -3x + 12

SINCE after solving X is any value , infinitely many solutions

↪3) 4 (x + 1) = 3x + 4

solving we get as , 4x+ 4 = 3x + 4 =》 X =0

only one solution

↪4) -2 (x-3) = 2x - 6

Only one solution

↪5) 6 (x + 5) = 6x + 11

NO SOLUTION

All the equations are solved by the distributive law of algebra
5 0
3 years ago
Read 2 more answers
May I please get help with other this problem for I am confused as I have tried multiple times to get the right answer
Aleks [24]

Using pythagoras

\begin{gathered} x^2=16^2+12^2 \\ x^2=256+144 \\ x^2=400 \\ \text{Take the square root} \\ x=20 \end{gathered}

The final answer

20

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1 year ago
The following data points are the number of games pitched by each of the Greenbury Goblins' starting pitchers last season.
Leviafan [203]

Answer: 1.87 games

Step-by-step explanation:

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3 years ago
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