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iVinArrow [24]
3 years ago
7

I need help with the area and perimeter

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

Area would be 122.

Perimeter would be 45.

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Find the interest<br> earned:<br> $26,000 for 36 months<br> at 7.5% annual<br> compound interest
stich3 [128]

Answer:

Interest = $6,300 (Approx.)

Step-by-step explanation:

Given:

Amount deposit (P) = $26,000

Number of month = 36 month

Number of year (n) = 36 / 12 = 3 year

Rate of interest (r) = 7.5% = 0.075  

Find:

Interest  earned

Computation:

Interest = p[(1+r)ⁿ-1]

Interest = 26,000[(1+0.075)³-1]

Interest = 26,000[(1.075)³-1]

Interest = 6,299.71

Interest = $6,300 (Approx.)

7 0
2 years ago
What is 120 degrees radians
jek_recluse [69]

Answer:

A 120 degrees in radians=2.0944

Hope this helps.

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2 years ago
Find the sum of the measures of the interior angles of a convex 37-gon.
denis-greek [22]
<span>There is an equation to solve this. It looks like: Sum of interior angles = (n - 2) * 180 degrees where n is the number of sides of the n-gon, which is 37.</span>
7 0
2 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
2 years ago
Help me pls 20 POINTS
Tema [17]

Answer:

bottom =80m^2

Side =50m^2

triangle = 3 ×8 ×5

6 0
2 years ago
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