Answer:
t = 6 s
Step-by-step explanation:
Given that,
Sherry is driving 390 miles to visit The gateway arch in St. Louis.
She drives at an average rate of 65 miles per hour.
We need to find the amount of time it will take Sherry to get to the arch. Let the time is t.
Speed = distance/time
Hence, it will take 6 hours to get to the arch.
A quadrilateral is any figure with 4 sides, no matter what the lengths of
the sides or the sizes of the angles are ... just as long as it has four straight
sides that meet and close it up.
Once you start imposing some special requirements on the lengths of
the sides, or their relationship to each other, or the size of the angles,
you start making special kinds of quadrilaterals, that have special names.
The simplest requirement of all is that there must be one pair of sides that
are parallel to each other. That makes a quadrilateral called a 'trapezoid'.
That's why a quadrilateral is not always a trapezoid.
Here are some other, more strict requirements, that make other special
quadrilaterals:
-- Two pairs of parallel sides . . . . 'parallelogram'
-- Two pairs of parallel sides
AND all angles the same size . . . . 'rectangle'
(also a special kind of parallelogram)
-- Two pairs of parallel sides
AND all sides the same length . . . 'rhombus'
(also a special kind of parallelogram)
-- Two pairs of parallel sides
AND all sides the same length
AND all angles the same size . . . . 'square'.
(also a special kind of parallelogram, rectangle, and rhombus)
It would be (3,0) and (0,3) respectively.
Answer:
Answer → C) 121°
Step-by-step explanation:
» Let the wanted angle be x
Finding a price that is 30% lower than $2075 is the same as finding a price that is 70% of $2075.
That means all we need to do is calculate what is 70% of $2075.
Convert 70% into decimal form which is 0.70.
Next, multiply $2075 by 0.70.
$2075*0.70 = $1452.50
The price the travel agent found was $1452.50
Note: If you don't know how to multiply by decimals you can multiply $2075 by 7 than divide the result by 10 (move the decimal point one place to the left).
