There's a fixed difference of 6 between terms (9 - 3 = 6, 15 - 9 = 6, and so on). The first term of the sequence is 3, so the 
-th term is
If there are 24 terms in the sum, then the last term is 6×23 - 3 = 135.
Let 
be the sum,
Reverse the order of terms:
If we add up the terms in the same positions, we get twice on the left side, while on the right side we observe that each pair of terms will sum to 138.
and since there are 24 terms in the sum, the right side is the sum of 24 copies of 138. In other words,
and solving for gives
Want to use some of the algebra rules of log's:
log(a)-log(b)= log(a/b),
so log(P/N) - log(M/N) = log( P/N:M/N) = log(P/M),
Then: 8-5 = log(P/M), log(P/M)=3.
If log here means natural logarithm (base e), then P/M = e^3,
If log here means basis 10, decimal logarithm, then P/M = 10^3 = 1000.
Answer:
m= 11/ 12
Step-by-step explanation:
hope that really helps
Answer:
125 to the 6th power.
Step-by-step explanation:
2 * 3 * 125 = 750
plz give brainly.
Sum of two numbers is 62?
Let's call the two numbers
and
let's find two same numbers that would add up to 62: 31.
31 + 31 = 62
since it said the difference is 8, we have to add 4 to one number and subtract 4 from another.
31 - 4 = 27
31 + 4 = 35
Therefore, the two numbers following the given rules are 27 and 35
