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jeyben [28]
3 years ago
10

2x^3 + 3x^2 -11x -6 divided by x - 2

Mathematics
1 answer:
Gnesinka [82]3 years ago
3 0

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

         x=2

therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

      = 2*8 + 3*4 - 11*2 - 6

      = 16 + 12 - 22 - 6

      = 28-28

     = 0

Hope it helped u, ^_^.

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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

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=16(1)-1/3+16-1/3

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Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

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