$\frac{6+\sqrt{27} }{4-\sqrt{3} } = \frac{r+s\sqrt{3} }{13} \\We\ may\ multiply\ the\ numerator\ and\ denominator\ with\ (4+\sqrt{3} ).\\Hence,\\\frac{(6+\sqrt{27})(4+\sqrt{3}) }{13} = \frac{r+s\sqrt{3} }{13} \\Hence,\\24+6\sqrt{3} +4\sqrt{27} +9= r+s\sqrt{3}\\24+6\sqrt{3} +4*3\sqrt{3} } +9= r+s\sqrt{3}\\24+6\sqrt{3} +12\sqrt{3}+9 = r+s\sqrt{3}\\33+18\sqrt{3} = r+s\sqrt{3}\\Hence,\\r=33, s=18$

5 0

3 years ago

How many solutions does the linear system below have? -8x+2y=6 and -4x+y=3

Verizon [17]

Answer:

Step-by-step explanation:

Try dividing the first equation by 3. The result will be identical to the second equation. Thus, we have two lines that coincide, and therefore there are an infinite number of solutions.

7 0

3 years ago

Re write the equation in standard form y=8x+2

quester [9]

Standard form: 8x - y = -2

5 0

3 years ago