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4 years ago

What value added to x2 + 2x would complete the square

Mathematics

2 answers:

Hoochie [10]4 years ago

8 0

To find the value take the b and divide it by two. then square it. here your b value is 2 so 2/2 is 1. squared is. 1.

Talja [164]4 years ago

5 0

Answer:

1 would complete the square

Step-by-step explanation:

In order to solve this you have to remember the formlua for the perfect quadratic trinomial:

$a^2 + 2 ab +b^2=0$

IN the example you have A^2 and 2ab, since A=1, then the 2x will resulto from the multiplication of b and a multiplied by 2, so we just have to divide 2x by 2x to get b:

$\frac{2x}{2x}=1$

So we get that b is 1.

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2/3+1/12 what's the answer

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3/4 or 9/12 make the denominators the same then just add

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3 years ago

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PLEASE HELP I WILL MARK BRAINLIEST!<br> Question is in the image.

deff fn [24]

Answer:

Step-by-step explanation:

The interquartile range of a data set is the difference between the upper and lower quartiles.

First, put the values in order from least to greatest:

8, 9, 9, 9, 10, 11, 13, 15, 17, 18, 22

To find the upper quartile, we need to first find the median.

The median of this data set is 11, because it is in the middle of the values.

The upper quartile is the median of all the numbers to the left of 11.

The median of 8, 9, 9, 9, and 10 is 9, because it's in the middle.

So the upper quartile is 9.

The lower quartile is the same, but to the right of 11. The median of 13, 15, 17, 18, and 22 is 17 because it's in the middle.

Now, to find the interquartile range, find the difference between 18 and 9.

17 - 9 = 8

5 0

3 years ago

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per

ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that $\mu = 2$

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

We want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

$P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902$

$P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176$

1.76% probability that in one hour more than 5 clients arrive

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4 years ago

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3 years ago

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