Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
Printer A prints for 10 minutes, so prints
... (30 pages/minute)×(10 minutes) = 300 pages
Printer B prints for 7 minutes, so prints
... (40 pages/minute)×(7 minutes) = 280 pages
At the end of 10 minutes, the two printers will have printed
... 300 pages + 280 pages = 580 pages
Answer:
y= 8x +7
Step-by-step explanation:
<u>slope-intercept form:</u>
y= mx +c, where m is the gradient (or slope) and c is the y-intercept.
Since it is a linear function, the gradient of any 2 points would be equal.
Thus, gradient of the line
Subst. m=8 into the equation:
y= 8x +c
To find the value of c, substitute a pair of coordinates.
When x=0, y= 7,
7= 8(0) +c
c= 7
Thus, the equation of the linear function is y= 8x +7.
Answer: 8 3/4
Step-by-step explanation:
3x(4x-5+3); where x is 1/2
Substitute the value 1/2 with x
3 1/2 (4 1/2 - 5+3)
7/2 (9/2 -2)
7/2 (5/2)
35/4 = 8 3/4
If the discriminant b^2-4ac is 0, then you have TWO EQUAL, REAL ROOTS.
If you're given the x-intercepts, you can determine the factors of the polynomial as follows: Take -3, change the sign and write (x+3). Take 5, change the sign and write (x-5). Then the eq'n of the parabola is
f(x) = (x+3)(x-5) = x^2 - 2x -15, in which a=1, b = -2 and c= -15.
You can find the x-coordinate of the vertex, which is also the equation of the axis of symmetry, using
x= -b / (2a). Here, x = -(-2) / (2[1]), or x = 1
Find the y-coordinate by subbing 1 for x in the equation above:
y = (1)^2 - 2(1) - 15 = 1 - 2 - 15 = -16
The vertex is at (1, -16) and the equation of the axis of symm. is x = 1.
