Answer:
Genotype: Bb (heterozygous)
Phenotype: brown fur
Explanation:
Since allele B is dominant to allele b, as long as genotype has allele B in it, its effect of phenotype will be expressed instead, regardless of whether allele b is present.
As mouse genotype is stated as Bb, on the chromosome from its parents, allele B comes from one parent while allele b is inherited from the other parent.
Phenotype is the expressed trait. In this case, as genotype has allele B, the phenotype will be brown fur as its effect is expressed.
Answer:
Metaphase
Explanation:
In prophase, spindle fibers start emerging from the centrosomes. In metaphase, the spindle fibers attach to the sister chromatids.
The number of producers is more than consumers and top carnivores in ecosystem. for example:- in the food chain of grass--goat--man,atleast 90% of energy is pasted to other level and 10% will be stored at that level it self.
grass goat man
50/100 40/80 30/60.
as we human beings depend on plants and animals for our food for our whole life we need atleast 100 numbers of small plants for one week.
A.The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals.
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.
B.To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>

<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:

=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>