1/2 = cos(2*t)sqrt(3) /2 = sin(-2*t)find tfind the time derivative of x(t), y(t)(-2sin(2*t) , -2cos(2*t) )plug in the t you found to find the velocity vector.
So the change in between terms is 5 so you would put 5x, then for the first term, which is 2, 5*1(x)(because it's first term) then the difference between 5-2(because it's the 2nd term) So you would plug 100 in for x so 5(100)-3=497. Hope this helped!
Answer:
Step-by-step explanation:
Given 
, start by squaring both sides to work towards isolating 
:
Recall 
and 
:
Isolate the radical:
Square both sides:
Expand using FOIL and 
:
Move everything to one side to get a quadratic:
Solving using the quadratic formula:
A quadratic in 
has real solutions 
. In 
, assign values:
Solving yields:
Only works when plugged in the original equation. Therefore, 
is extraneous and the only solution is 
Answer:
<h2>12 </h2>
Step-by-step explanation:
<h2>2.5x = 30</h2><h2>x = 30 / 2.5</h2><h2>x = 12</h2>
