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Vikki [24]
2 years ago
11

The length of 2 sides of a triangle are 12 inches and 4 inches. Which is the third side?

Mathematics
1 answer:
Westkost [7]2 years ago
7 0

Answer:

Let x = the third side

 

In a triangle, the sum of any 2 sides must be larger than the third side.

I believe this is called the triangle inequality theorem.

 

We can construct 3 inequalities to obtain the range of values for the third side.

 

  (Inequality #1)   12 + 4 > x

                                  16 > x

 

  (Inequality#2)    12 + x > 4

                                    x > -8   (we can discard this ... we know all sides will be positive)

 

  (Inequality #3)   4 + x > 12

                                   x > 8

 

So when we combine these together,  

 

   8 < x < 16

 

X (the third side) must be a number between 8 and 16. but not including 8 and 16

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Could somebody help me with Geometry? THANKS!!!!!!!!!!!!!!!!!!!!!
Vedmedyk [2.9K]

I'll do problem 1 to get you started.

The answer to problem 1 is <u>3400 miles</u>

============================================================

Explanation for problem 1:

We're asked to find the perimeter, which is the total distance around the exterior or outside. In other words, we need to add up the four side lengths of this quadrilateral.

We'll need the distance formula to find the lengths of the slanted sides AB and BC

----------------------------------------

Let's first find the length of segment AB

A = (x1,y1) = (0,0)

B = (x2,y2) = (400,300)

d = Length of AB

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-400)^2 + (0-300)^2}\\\\d = \sqrt{(-400)^2 + (-300)^2}\\\\d = \sqrt{160000 + 90000}\\\\d = \sqrt{250000}\\\\d = 500\\\\

The distance from A to B is 500 miles. This is the same as saying segment AB is 500 miles long.

----------------------------------------

Now find the length of segment BC

B = (x1,y1) = (400,300)

C = (x2,y2) = (-800,800)

d = length of BC

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(400-(-800))^2 + (300-800)^2}\\\\d = \sqrt{(400+800)^2 + (300-800)^2}\\\\d = \sqrt{(1200)^2 + (-500)^2}\\\\d = \sqrt{1440000 + 250000}\\\\d = \sqrt{1690000}\\\\d = 1300\\\\

----------------------------------------

The length of CD is fairly easy to find without needing the distance formula. This is because it is a vertical line. We subtract the y coordinates of C and D to get 800-0 = 800. So CD is 800 miles long.

Segment DA is a similar story. But we subtract the x coordinates. This only works for horizontal lines. DA is 800 miles long because |-800-0| = 800. Absolute value is used to make sure the distance is never negative.

----------------------------------------

To summarize everything so far, we found these four side lengths

  • AB = 500
  • BC = 1300
  • CD = 800
  • DA = 800

The perimeter is going to be the sum of those four sides, leading to...

perimeter = sum of sides

perimeter = AB+BC+CD+DA

perimeter = 500+1300+800+800

perimeter = 3400 miles

This is the total distance traveled if you started at city A, went to B, then to C, then to D, and then finally went back to A.

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