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Lemur [1.5K]
3 years ago
7

On a math quiz, you earn 10 points for each question answered correctly. In the equation below, x represents the number of quest

ions that you answer correctly on this quiz, and y represents the total number of points you score on this quiz. The relationship between these two variables is modeled by the equation y = 10x.
What is the independent variable?
A) The value of 10 in the equation.
B) The total number of points scored on the exam.
C) The number of questions answered correctly on the exam.
D) The independent variable cannot be determined from the given information.
Mathematics
2 answers:
olga_2 [115]3 years ago
8 0

Answer: The answer is B i know this bc i took the test

Step-by-step explanation:

Neko [114]3 years ago
4 0

Answer:The answer is c.

Step-by-step explanation:

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Write each fraction as a decimal 4/50
Len [333]
4/50 as a decimal is .08   
 Divide 4 by 50
8 0
2 years ago
37. Bowling Alley A charges $5 admission and $3.50 per game. Bowling Alley B
sdas [7]

a. The cost for A = 19, and B = 25.

b. The cost for A = 22.25, and B = 25

c. When you want to play more than five games.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

a. How much does it cost to play four games at each bowling alley?

a. 5 + 3.50 × 4 = 19, B is always $25

b. How much does it cost to play five games at each bowling alley?

b. 5 + 3.50 × 5 = 22.25, B is always $25

c. When is it financially more beneficial to bowl at Bowling Alley B?

c. 5 + 3.50 × 6 = 26, six games cost more than $25.

We can see from the solution that for any number of times we will be charged $25 but for less than 5 times the charges of B will be higher than the charges of A.

Therefore a.The cost for A = 19, and B = 25.The cost for A = 22.25, and B = 25 When you want to play more than five games.

To know more about expression follow

brainly.com/question/723406

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5 0
1 year ago
Helppppppppppoppppppppppppppppppp
NARA [144]
I think the answer would be the last one. a cylinder with radius 4 units.
3 0
2 years ago
a line is perpendicular to y = 3/7x - 2 and intersects the point (3,3). What is the equation of this perpendicular line?
snow_lady [41]

Answer:

y = -7/3x + 10

Step-by-step explanation:

Step 1: Find the slope of the perpendicular line

Do this by taking the negative inverse of the first line

m = -7/3

Step 2: Find <em>b</em>

y = mx + b

y = -7/3x + b

3 = -7/3(3) + b

3 = -7 + b

b = 10

You should get y = -7/3x + 10 as your final answer.

6 0
2 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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