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9966 [12]
3 years ago
11

What characteristic do all living things share?

Chemistry
2 answers:
BARSIC [14]3 years ago
8 0

All organisms share certain characteristics of life, for example, all living things are made of cells and they must reproduce to make the next generation. Without these characteristics, there is no life.

I hope i helped??

kupik [55]3 years ago
6 0

Answer:

eyes and mouth

Explanation:

smell,touch, taste,see

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A student is told that both energy and mass must be conserved in every chemical reaction. She measures the mass of Hydrochloric
salantis [7]

Answer:

Explanation:

When we react Hydrochlorid Acid with zinc we have the following reaction:

2HCl(aq) + Zn(s) --> ZnCl2(aq) + H2(g)

The hydrogen gas formed is lost to the environment, so we can affirme that in the start we have the mass for all the H, Cl and Zn atoms in the solution, but after the reaction occurs, we have only the mass for the Cl and Zn atoms.

That's why the mass is less than the original.

The law that the student was told is only applied to closed environments.

6 0
3 years ago
Read 2 more answers
NH4Cl + AgNO3 → AgCl + NH4NO3
iVinArrow [24]
<h3><u>A</u><u> </u><u>N</u><u> </u><u>S</u><u> </u><u>W</u><u> </u><u>E</u><u> </u><u>R</u><u> </u><u>:</u><u> </u><u>–</u><u> </u></h3>

  • It's a balanced equation!
  • This is a precipitation reaction.
  • AgCl is the formed precipitate.
7 0
2 years ago
Ethylene oxide (EO) is prepared by the vapor-phase oxidation of ethylene. Its main uses are in the preparation of the antifreeze
Rashid [163]

Answer:

a. ΔH^0_{rxn} = -108.0\frac{kJ}{mol}

b. 320.76° C

Explanation:

a.)

we can solve this type of question (i.e calculate ΔH^0_{rxn} , for the gas-phase reaction )  using the Hess's Law.

ΔH^0_{rxn} =  E_{product} deltaH^0_{t}-E_{reactant} deltaH^0_{t}

Given from the question, the table below shows the corresponding  ΔH^0_{t}(kJ/mol) for each compound.

Compound                    H^0_{t}(kJ/mol)

Liquid EO                       -77.4

CH_4_(g_)                            -74.9                

CO_(g_)                              -110.5

If we incorporate our data into the above previous equation; we have:

ΔH^0_{rxn} = (-110.5 kJ/mol + (-74.9 kJ/mol) ) - (-77.4 kJ/mol)

          =   -108.0 \frac{kJ}{mol}

b.)

We are to find the final temperature if the average specific heat capacity of the products is 2.5 J/g°C

Given that:

the specific heat capacity (c) = 2.5 J/g°C

T_{initial} = 93.0°C   &

the  enthalpy of vaporization  (ΔH^0_{vap}) = 569.4 J/g

If, we recall; we will remember that; Specific Heat Capacity is the amount of heat needed to raise the temperature of one gram of a substance by one kelvin.

∴ the specific heat capacity (c) is given as =  \frac{Heat(q)}{mass*changeintemperature(T_{initial}-T_{final})}

Let's not forget as well, that  ΔH^0_{vap} = \frac{q}{mass}

If we substitute  ΔH^0_{vap}  for  \frac{q}{mass} in the above equation, we have;

specific heat capacity (c) = \frac{deltaH^0_{vap}}{T_{final}-T_{initial}}

Making (T_{final}- T_{initial}) the subject of the formula; we have:

T_{final}- T_{initial}  = \frac{delat H^0_{vap}}{specificheat capacity}

(T_{final}-93.0^0C)=\frac{569.4J/g}{2.5J/g^0C}

T_{final}=\frac{569.4J/g}{2.5J/g^0C}+93.0^0C

         = 227.76°C +93.0°C

          = 320.76°C

∴ we can thereby conclude that the final temperature = 320.76°C                

7 0
3 years ago
In chemical reactions, the number of atoms in the product is ________________.
irina1246 [14]

Answer:

A

Explanation:

7 0
3 years ago
6th grade help me plzzzzzz
Anna [14]

Answer:

<h2><u><em>It's protons and neutrons </em></u></h2>

Explanation:

<h2><u><em>Hope this helps </em></u></h2>
3 0
3 years ago
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