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3 years ago

A scuba diver started at 22 ft above sea level, then descended 40 ft. What integer best represents his new attitude?

Mathematics

2 answers:

jonny [76]3 years ago

6 0

I think it is 62? Idk I added the 40 and 22.

frez [133]3 years ago

4 0

The best integer that best defines his new altitude would be -18 because you have so subtract 40 from 22 and then get -18ft.

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In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and

zhannawk [14.2K]

Answer:

b. 3

Step-by-step explanation:

Here, n players score 2 points and m players score 5 points,

So, total scores = 2n + 5m,

According to the question,

The total number of points is 50,

⇒ 2n + 5m = 50

Since, n and m can be any positive integers including 0 ( because number of players can not be negative or in fraction )

Also, for the positive integer value of m, n must be the multiple of 5 less than or equal to 25,

Thus, the possible values of m and n are,

(5,8), (10, 6), (15, 4), (25,0),

Since, 8-5 < 10-6 < 15-4 < 25-0

Hence, the least possible positive difference between n and m is 3.

Option 'b' is correct.

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3 years ago

What happens if the red lines are NOT paralell. Which angle types are still congruent?

jekas [21]

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4 0

2 years ago

Read 2 more answers

Simplify the rational expression. state any restrictions on the variable. n^4-11n^2+30/n^4-7n^2+10

Andrej [43]

For this case we have the following expression:
 $\frac{n ^ 4-11n ^ 2 + 30}{ n ^ 4-7n ^ 2 + 10} 

$
 We are going to make the following change of variables:
 $x = n ^ 2
$
Rewriting the expression we have:
 $\frac{(x ^ 2-11x + 30)}{(x ^ 2-7x + 10)} 

$
Factoring the expression we have:
 $\frac{(x-5) (x-6)}{(x-5) (x-6)} 
$
Canceling similar terms we have:
 $\frac{x-6}{x-2} 
$
Returning the change we have:
 $\frac{n ^ 2-6}{n ^ 2-2} 

$
 The resctrictions of the function are those that make the denominator equal to zero.
We have then:
 $n ^ 2-2 = 0

n = +/- \sqrt{2} 
$
 Answer:
The simplified expression is:
 $\frac{n ^ 2-6}{n ^ 2-2}$
The restrictions are:
 $n = \sqrt{2} 
$
$n = - \sqrt{2}$

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3 years ago

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makkiz [27]

Answer:

c. 50

Step-by-step explanation:

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3 years ago

Find the value of y if the value of x is 2 for each equation and match it with the appropriate result.

Xelga [282]

9514 1404 393

Answer:

3, 0, 2, -2

Step-by-step explanation:

Put x=2 into each equation and solve for y.

2 + y = 5

y = 5 -2

y = 3

3x +2y = 6

3·2 +2y = 6

2y = 6 -6 = 0

y = 0

2x +y = 6

2·2 +y = 6

y = 6 -4

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5·2 +3y = 4

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y = -2

4 0

3 years ago