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grin007 [14]
2 years ago
10

Write the following in terms of sin θ only. cot θ

Mathematics
1 answer:
sveta [45]2 years ago
6 0
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
cos(\theta)=\pm\sqrt{1-sin^2(\theta)}\\\\
-----------------------------\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\implies cot(\theta)=\cfrac{\pm\sqrt{1-sin^2(\theta)}}{sin(\theta)}
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lora16 [44]

Answer: I think it's C


Step-by-step explanation:

(83-64)-(64+29)

83-64=19

64+29=93      

<u><em>19x-93</em></u>

3 0
3 years ago
Hi, i need help with this question. Thank you so much if you decide to help me :3
irina1246 [14]

Answer:

We can split this into ∛8 * ∛n⁹. ∛8 = 2 and ∛n⁹ = n³ so the answer is 2n³.

7 0
3 years ago
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6
8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16     Eqn 1

8x+5y=113    Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80    Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

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Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0
2 years ago
The average discharge at the mouth of the Amazon River is 4,900,000 cubic feet per second. How much water is discharged from the
Misha Larkins [42]

Answer:  Average discharge at the mouth of the Amazon River in 1 hour = 1.764\times 10^{10} cubic feet

Average discharge at the mouth of the Amazon River in 1 year= 3.66912\times10^{13} cubic feet[/tex]

Step-by-step explanation:

Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.

i.e. The average discharge at the mouth of the Amazon River  in 1 second= 4,900,000 cubic feet

Since 1 hour = 3600 seconds

Then , the average discharge at the mouth of the Amazon River  in 1 hour =

4900000\times3600=17640000000 cubic feet

Since , there are 2080 hours in a typical year.

Then, the average discharge at the mouth of the Amazon River in 1 year=

2080\times17640000000\\\\=36,691,200,000,000=3.66912\times10^{13} cubic feet

6 0
2 years ago
Which expresses 6y : 9y in its simplest form? A. 9 : 6 B. 2 : 3 C. 6 : 9 D. 3 : 2
Monica [59]
If you divide each number, 6:9, by 3 you will get the simpliest form. My answer will have to be B. 2:3
3 0
3 years ago
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