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castortr0y [4]
3 years ago
15

Find two positive consecutive odd integers whose products is 99.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

9,11

Step-by-step explanation:

let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)

therefore;

x(x+2)= 99

x²+2x=99

I usually solve the sum like this,

we need to find the nearest square number ( number smaller than the number on the R.H.S)

here, it is 81, whose square root is 9. therefore the solution is 9

verification:

(9)²+2*9=99

81+18=99

99=99

hence, 9 is the solution. therefore the positive odd consecutive integers are  

x=9

x+2=9+2= 11

verification:

9*11=99

99=99

L.H.S=R.H.S

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hope this helps
4 0
3 years ago
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mr_godi [17]
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6 0
2 years ago
Juanita wants to buy 12.5 pounds of stones to decorate her garden. The stone normally sells for $1.80 a pound. The salesman offe
anastassius [24]

Step-by-step explanation:

$1.80 per pound

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What is the hcf of 45 and 100
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Answer:

45 100

/ \ / \

3 × 15 2×50

/ \ / \

3× 5 2×25

/ \

5×5

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100: 2×2×5×5

common : 3×5

15

HCF: 15

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2 years ago
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