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castortr0y [4]
3 years ago
15

Find two positive consecutive odd integers whose products is 99.

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

9,11

Step-by-step explanation:

let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)

therefore;

x(x+2)= 99

x²+2x=99

I usually solve the sum like this,

we need to find the nearest square number ( number smaller than the number on the R.H.S)

here, it is 81, whose square root is 9. therefore the solution is 9

verification:

(9)²+2*9=99

81+18=99

99=99

hence, 9 is the solution. therefore the positive odd consecutive integers are  

x=9

x+2=9+2= 11

verification:

9*11=99

99=99

L.H.S=R.H.S

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the sum of three numbers is 79. The second number is 5 times the first, while the third is 16 more than the first. Find the numb
swat32
Let the 1st number be x; 2nd number be y; 3rd number be z.

x + y + z = 79

x = number we are looking for.
y = x * 5 ==> 5 times the first
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Therefor,

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