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tankabanditka [31]

3 years ago

12

What is the speed of light. Don't look it up. challenge excepted?

2 answers:

san4es73 [151]3 years ago

8 0

300,000,000 seconds -------------

Leokris [45]3 years ago

8 0

<span>299 792 458 m / s is the answer

</span>

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A scale drawing of a school bus has a scale of 1/2 inch to 5feet. If the length of the school bus is 4 1/2 inches on the scale d

Sedaia [141]

Answer: actual length = 45 ft

Explanation:

Scale drawn:

1/2 inch = 5ft

Meaning that if the drawing scale is 0.5 inch then the actual bus would be 5ft.

If the length of the drawn school bus is 4 1/2 inches. We can write:

1/2 = 5
4 1/2 = x

=> x = (5 x 4 1/2)/1/2
Or x = (5 x 4.5)/0.5
x = 22.5/0.5
x = 45

Therefore the actual length of the bus is 45 ft

3 0

3 years ago

A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is

kakasveta [241]

Answer:

10/54 = 0.185

8 0

3 years ago

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suter [353]

Answer: 38

Step-by-step explanation:

3.8=19/5

u have to flip the reciprocal to divide by fraction so 1/10 will be just 10

Then u get 19/5 x 10

You can reduce the GCF so it would be 19 x 2

19 x 2 = 38

Or you can plug it into your calculator (3.8 x .1)

3 0

2 years ago

PLEASE HELP ASAP WILL GIVE BRAINLEIST!!<br> Find the missing side in the similar figures below:

quester [9]

Answer:

9 Elmo

Step-by-step explanation:

3 0

3 years ago

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the <u>first differences</u> between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are <u>not the same</u>, we need to calculate the <u>second differences</u>:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the <u>same</u>, the relationship between the variable is quadratic and will contain an $x^2$ term.

--------------------------------------------------------------------------------------------------

<u>To determine the quadratic equation</u>

The coefficient of $x^2$ is always <u>half</u> of the <u>second difference</u>.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago