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BlackZzzverrR [31]
3 years ago
8

How do you solve 38.7×10 to the fourth power

Mathematics
1 answer:
faltersainse [42]3 years ago
8 0

ndex Notation and Powers of 10

10 to the Power 2

The exponent (or index or power) of a number says

how many times to use the number in a multiplication.

102 means 10 × 10 = 100

(It says 10 is used 2 times in the multiplication)

Example: 103 = 10 × 10 × 10 = 1,000

In words: 103 could be called "10 to the third power", "10 to the power 3" or simply "10 cubed"

Example: 104 = 10 × 10 × 10 × 10 = 10,000

In words: 104 could be called "10 to the fourth power", "10 to the power 4" or "10 to the 4"

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Which of the following represents the additive inverse of 12
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Suppose that two balanced, six sided dice are tossed repeatedly and the sum of the two uppermost faces is determined on each tos
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Step-by-step explanation:

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Use the Euclidean Algorithm to compute the greatest common divisors indicated. (a) gcd(20, 12) (b) gcd(100, 36) (c) gcd(207, 496
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Answer:

(a) gcd(20, 12)=4

(b) gcd(100, 36)=4

(c) gcd(496,207 )=1

Step-by-step explanation:

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em>                                   Given integers </em>a, b<em>, find </em>d=gcd(a,b)<em />

Here is an outline of the steps:

  1. Let a=x, b=y.
  2. Given x, y, use the division algorithm to write x=yq+r.
  3. If r=0, stop and output y; this is the gcd of a, b.
  4. If r\neq 0, replace (x,y) by (y,r). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

(a) To find gcd(20, 12) we apply the Euclidean algorithm:

20 = 12\cdot 1 + 8\\ 12 = 8\cdot 1 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(20, 12)=4.

(b) To find gcd(100, 36) we apply the Euclidean algorithm:

100 = 36\cdot 2 + 28\\ 36 = 28\cdot1 + 8\\ 28 = 8\cdot 3 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(100, 36)=4.

(c) To find gcd(496,207 ) we apply the Euclidean algorithm:

496 = 207\cdot 2 + 82\\ 207 = 82\cdot 2 + 43\\ 82 = 43\cdot 1 + 39\\ 43 = 39\cdot 1 + 4\\ 39 = 4\cdot 9 + 3\\ 4 = 3\cdot 1 + 1\\ 3 = 1\cdot 3 + 0

The process stops since we reached 0, and we obtain gcd(496,207 )=1.

3 0
3 years ago
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