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Natalka [10]
3 years ago
11

What is the area of this rectangle? (Picture is above) I WILL PUT BRAINLIEST!!

Mathematics
2 answers:
LenKa [72]3 years ago
7 0
The answer should be 84.7cm
hope this helps
kompoz [17]3 years ago
3 0
Hi! the area of the rectangle would be: 84.7cm. Have a nice day! :)
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How do I find the zeros of x^4-10x^3-66x^2-94x-39
Gennadij [26K]

Answer: x = -1, -3, 7 + √62, 7 - √62


Step-by-step explanation:

q                                    p

x⁴ - 10x³ - 66x² - 94x - 39

\frac{p}{q} = +/- \frac{1*3*13*39}{1}

possible rational factors: 1, -1, 3, -3, 13, -13, 39, -39

Use synthetic division <em>or long division</em> to see which factor will leave a remainder of 0.

try x + 1 = 0  ⇒   x = -1

-1   |  1     -10     -66     -94     -39

    <u>|  ↓     -1        11        55      39 </u>

       1     -11      -55     -39       0

(x + 1)(x³ - 11x² - 55x - 39)        

next, try x + 3 = 0  ⇒   x = -3   <em>for the new polynomial</em>

-3   |  1     -11     -55     -39

     <u>|  ↓     -3       42     39</u>

        1     -14      -13       0  

(x + 1)(x + 3)(x² - 14x - 13)

Lastly: find the zeros by setting each factor equal to zero and solve.

x + 1 = 0  ⇒  x = -1

x + 3 = 0   ⇒ x = -3

x² - 14x - 13 = 0

x = \frac{-(b) +/- \sqrt{(b)^{2} -4(a)(c)}}{2(a)}

  = \frac{-(-14) +/- \sqrt{(-14)^{2} -4(1)(-13)}}{2(1)}

  = \frac{14 +/- \sqrt{196+52}}{2}

  = \frac{14 +/- \sqrt{248}}{2}

  = \frac{14 +/- 2\sqrt{62}}{2}

  = 7 +/- \sqrt{62}


5 0
3 years ago
Q=
wolverine [178]

Answer:

Good Luck!

Step-by-step explanation:

6 0
3 years ago
PLEASE pHKEP I AM BEGGING YOU OLEASEEEEEEEE!!!!!!! I GIVE EXTRA POINTS AND BRAINLIEST!!!!
AVprozaik [17]
Use lower or greater signs
6 0
3 years ago
Which statement best describes why there is no real solution to the quadratic equation y = x2 - 6x + 13?
Ahat [919]
This is the quadratic equation
x = -b +/- (sq root)(b^2 - 4(a)(c) all over 2a
If inside the square root the value is <0. You can't get an answer.
Now figure the rest out
6 0
3 years ago
Oints Q and R are midpoints of the sides of triangle ABC.
MariettaO [177]

Answer:

AQ = 20 units

Step-by-step explanation:

Comparing triangle AQR to ABC,

\frac{AQ}{AB} = \frac{QR}{BC}

\frac{4p}{8p} = \frac{2p + 3}{6p-4}

cross multiply and make p the subject of formula, we have:

8p (2p+3) = 4p(6p-4)

16p^{2} + 24p = 24p^{2} - 16p

24p + 16p = 24p^{2} - 16p^{2}

40p = 8p^{2}

divide through by 8p,

p = 5

Therefore, AQ = 4p

                        = 4 × 5

                        = 20

AQ = 20 units

3 0
3 years ago
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