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3 years ago

Consider the graph shown. the Which function could this graph represent?

Mathematics

2 answers:

Sever21 [200]3 years ago

4 0

There is no graph. you need to attach a picture, you can’t get your questions answered like that

Nikolay [14]3 years ago

3 0

There is no graph shown

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Does this graph represent a function? Why or why not?

DedPeter [7]

Answer: C

Step-by-step explanation: For a function, each x-coordinate corresponds to exactly one y-coordinate.

To determine whether the graph shown here

is a function, we can use the vertical line test.

The vertical line test tells us that if each x-coordinate on the graph corresponds to exactly one y-coordinate, then any vertical line that we draw on the graph should hit the graph at only one point.

For the graph show here, any vertical line that you draw with hit the graph at only one point which means it does pass the vertical line test.

So this graph is a <em>function</em>.

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3 years ago

Does this app actually work for ya'll????

Llana [10]

Answer:

Yessssss!

Step-by-step explanation:

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2 years ago

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Which graph represents g(x)=(x−3)2−5 ?

777dan777 [17]

The one on the top right

4 0

3 years ago

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The volume of a cube is 7.14 cubic meters. What is the cross-sectional area that is parallel to one of its faces?

Snowcat [4.5K]

Answer:

A = 3.706 square meters

Step-by-step explanation:

the length of a cube has equal side.

therefore, the volume of a cube is given by S³

V = S³ = 7.14

where S is the length of a side

the surface area of a cube is = 6S²

where the area a aside is calculated, then it is multiply by 6.

if S³ = 7.14

S = ∛(7.14) = 1.925 m

What is the cross-sectional area that is parallel to one of its faces?

this is saying we should calculate for the cross-sectional area of one face. All faces in a cube is equal and parallel to each other.

the crossectional area of one side of a cube is = S² = 1.925² = 3.706 square meters

A = 3.706 square meters

8 0

3 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

2 years ago

Read 2 more answers