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3 years ago

Solve for x. Find the angle measures. Angle AOB=x+3, angle AOC=2x+11, angle BOC=4x-7

Mathematics

2 answers:

Ghella [55]3 years ago

4 0

Answer:

x=5

AOB = 8

BOC = 13

AOC = 21

Step-by-step explanation:

Angle AOB and Angle BOC is equal to Angle AOC.

AOB = x+3

BOC = 4x-7

AOC= 2x+11

AOB + BOC = AOC

x+3+4x-7 = 2x+11

5x-4 = 2x+11

3x = 15

x = 5

Therefore, the value of x is 5.

Angle AOB = x+3

AOB = 5+3

AOB = 8

Angle BOC = 4x-7

BOC = 4(5)-7

BOC = 13

Angle AOC = 2x+11

AOC = 2(5)+11

AOC = 21

kolezko [41]3 years ago

4 0

Answer:

x=5

$\angle AOC=21$

$\angle AOB=8$

$\angle BOC=13$

Step-by-step explanation:

We are given that

$\angle AOB=x+3$

$\angle AOC=2x+11$

$\angle BOC=4x-7$

We have to solve for x and find the angle measures

$\angle AOC=\angle AOB+\angle BOC$

$2x+11=x+3+4x-7$

$2x+11=5x-4$

$11+4=5x-2x$

$15=3x$

$x=\frac{15}{3}=5$

Substitute the value of x then, we get

$\angle AOC=2(5)+11=21$

$\angle AOB=5+3=8$

$\angle BOC=4(5)-7=13$

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