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3 years ago

Do 2 and 3, please. show all your work

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

4 0

The answer is b and c

nignag [31]3 years ago

3 0

The answer would be b and c

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PLEASE, I NEED HELP FOR A CLASS. The length of triangle base is 26. A line, which is parallel to the base divides the triangle i

sasho [114]

Answer:

$DE=18.38$

Step-by-step explanation:

It is given that the length of triangle base is 26 that is BC=26.

A line, which is parallel to the base divides the triangle into two equal area parts.

Therefore, from the given information, $\frac{{\triangle}ADE}{ar ABC}=\frac{1}{2}$ .

Now, since it is given that A line, which is parallel to the base divides the triangle into two equal area parts, thus

$\frac{ar ADE}{arABC}=\frac{1}{2}=\frac{(DE)^{2}}{(BC)^{2}}$

⇒ $\frac{(DE)^{2}}{(BC)^{2}}=\frac{1}{2}$

⇒ $\frac{(DE)^{2}}{(26)^{2}}=\frac{1}{2}$

⇒ $(DE)^{2}=13{\times}26=338$

⇒ $DE=18.38$

7 0

3 years ago

It took Samantha 324 minuets to cook an 18 pound turkey. How many minutes per pound did it take to cook the turkey

Natalka [10]

18 min per pound

324 min. = X
______ _____
18 1 pound

324 x 1 = 324 324/18= 18 pounds

Cross multiply then divide as above.

5 0

3 years ago

£250 in the ratio 4 to 1

Andrej [43]

In the event that you are asking to devide parts, we will use the equation

·X+X²=Y

We Plug in our parts

·4x+1x=5x(Y)

We then substitute

·4x+1x=250(5x)

Then we devide Y(250) by the number of parts total.

·5 parts total.

·250/5=50

·1 part=50.

Next we substitute.

·200(4)+50(1)=250(5)

-In conclusion your answer is 50£:200<span>£, i hope this is the answer you are looking for, feel free to post your questions here in brainly in the future.</span>

4 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

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HELP ME PLease with this

Nikitich [7]

Answer:

Trump 2020 is the best

Step-by-step explanation:

8 0

3 years ago