Statements
2. right triangle
3. PQ = OP
5. ∆ONP = ∆PQO
Reasons
1. Given
4. Given
5. SAS
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The time taken for radio signal to the earth's surface we shall proceed as follows;
time=(distance)/(speed)
Distance=7.5×10^6 meters
speed=3×10^8 meters/second
therefore:
Time=(7.5×10^6)/(3×10^8)=0.025 seconds
We conclude that it will take the signal 0.025 seconds to reach the surface of the earth.
3) 18v2−15v−18
=3(6v2−5v−6)
=3(2v−3)(3v+2)
Answer:
That would be C
Step-by-step explanation:
