All categories

3 years ago

PLZZZ HELPPP THIS IS DUE!!

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

Answer:

y=3x-2..... i

x-y=4...... ii

x-4=y

Substituting the value of y in equation i,

x-4=3x-2

2-4=3x-x

-2=2x

x=-1.

From ii,

-1-4=y

y=-5.

x=-1, y=-5

Step-by-step explanation:

brainest please

You might be interested in

Part 4. NO LINKS!! Find the area of the shaded area shown. SHOW WORK PLEASE !! #21

SIZIF [17.4K]

Area of square

32²
1024

Radius of each circle

32/4/2
8/2
4

Area of 16 circles

16πr²
16π(4)²
16π(16)
256π
803.8cm²

Area of shaded region

1024-803.8
220.2cm²

5 0

2 years ago

Read 2 more answers

PROBABILITY QUESTION!!! PLEASE HELP

Evgen [1.6K]

Answer:

The answer is 8/5 or 8 out of 5.

Step-by-step explanation:

In order to solve this you need to first add the number of envelopes together to get the sum of how many envelopes there are, 1 + 3 + 2 + 2 = 8. Next you add the amount of blue and green envelopes together 3 + 2 = 5. The total number of envelopes is 8, and 5 out of the 8 are green or blue, therefore you will have a 8 out of 5 chance of picking one of those colors.

4 0

3 years ago

2/6 - 7/20 as a proper fraction or mixed number

trapecia [35]

Answer:

2/6 - 7/20 is -1/60 in fraction form.

4 0

3 years ago

Read 2 more answers

Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA

liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

$\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

We take left hand side of the given equation and solve it,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}$

Since, abc = 1,

$\frac{1}{c}=ab$ and c = $\frac{1}{ab}$

By substituting these values in the expression,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}$