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3 years ago

What is the diameter of the base of the cone below, to the nearest foot, if the volume is 314 cubic feet? Use π = 3.14.

Mathematics

1 answer:

guajiro [1.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

height of cone is not given.

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3 years ago

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MrMuchimi

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2 years ago

A random sample of size n1 = 16 is selected from a normal population with a mean of 75 and standard deviation of 8. A second ran

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3 years ago

What is the measure in degree of an angel that represents 50/350 of a circle

lawyer [7]

Answer:

do you mean 50/360? if 50/360 it is 50 degrees

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7 0

3 years ago

Let S denote the plane region bounded by the following curves:

oee [108]

The volume of the solid of revolution is approximately 37439.394 cubic units.

<h3>How to find the solid of revolution enclosed by two functions</h3>

Let be $f(x) = e^{\frac{x}{6} }$ and $g(x) = e^{\frac{35}{6} }$ , whose points of intersection are $(x_{1},y_{1}) =(0,1)$ , $(x_{2}, y_{2}) = (35, e^{35/6})$ , respectively. The formula for the solid of revolution generated about the y-axis is:

$V = \pi \int\limits^{e^{35/6}}_{1} {f(y)} \, dy$ (1)

Now we proceed to solve the integral: $f(y) = 6\cdot \ln y$

$V = \pi \int\limits^{e^{35/6}}_{1} {6\cdot \ln y} \, dy$ (2)

$V = 6\pi \int\limits^{e^{35/6}}_{1} {\ln y} \, dy$

$V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}$

$V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]$

$V = 35\pi\cdot (e^{35/6}-1)$

$V \approx 37439.392$

The volume of the solid of revolution is approximately 37439.394 cubic units. $\blacksquare$

To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504

8 0

2 years ago