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s2008m [1.1K]
4 years ago
15

What is the GCF? 5x + 25

Mathematics
2 answers:
Sunny_sXe [5.5K]4 years ago
6 0

Answer:

The GCF is 5

Step-by-step explanation:

<u>Step 1:  Find the GCF</u>

To find the GCF, divide both terms by 5.

5(x + 5)

So... the GCF is 5

Answer:  The GCF is 5

navik [9.2K]4 years ago
5 0

Answer:

<u>5</u>

Step-by-step explanation:

Since 5x,25 contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.

Steps to find the GCF for 5x,25:

1. Find the GCF for the numerical part 5,25

2. Find the GCF for the variable part x1

3. Multiply the values together

Find the common factors for the numerical part: 5,25

The factors for 5 are −5,−1, 1,5.

The factors for 25 are −25,−5,−1, 1,5,25.

List all the factors for 5,25 to find the common factors.

5: −5, −1, 1,5

25: −25, −5, −1, 1, 5, 25

The common factors for 5,25 are −5,−1,1,5.−5,−1,1,5

The numbers do not contain any common variable factors. The GCF (HCF) of the numerical factors −5,−1,1,5 is 5.

5

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Xelga [282]

Answer:

The answer in each numeral is:

  1. <u>f(4) = 28</u>
  2. <u>f(10) = -19</u>
  3. <u>f(-5) = -33</u>
  4. <u>f(9) = -9</u>

Step-by-step explanation:

To obtain the result in each case, you must replace the variable (n) by the value that appears in the second case, I'll explain it with the first exercise:

  • 1. f(n) = 5n + 8
  •   f(4) = ?

As you can see, in the second doesn't appear f(n), but f(4), that means you must replace the "n" in the equation by 4, if we do this, we obtain:

  • 1. f(4) = 5*(4) + 8
  • f(4) = 20 + 8
  • <u>f(4) = 28</u>

The first answer is 28, now we'll continue with the next exercises:

  • 2. f(n) = -2n + 1
  • f(10) = -2*(10) + 1
  • f(10) = -20 + 1
  • <u>f(10) = -19</u>

  • 3. f(n) = 6n - 3
  • f(-5) = 6*(-5) - 3
  • f(-5) = -30 - 3
  • <u>f(-5) = -33</u>

  • 4. f(n) = -n
  • <u>f(9) = -9</u>

In this form, <u><em>you can prove the answers are: 28, -19, -33, and -9 respectively</em></u>.

8 0
4 years ago
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