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blsea [12.9K]
3 years ago
14

Use the product to sum formulas to write the product as a sum or difference

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0
Ok can you please show the formula or give more information please
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In autumn a tree starts to shed its leaves. 2/5 of the leaves fall off in the first week. 1/2 of those remaining fall of in the
Oduvanchick [21]

Answer:

850 leaves were on the tree initially.

Same as;

2/5 + 1/5 + 3/10 + (remaining leaves 1/10) = 1

4/10 + 2/10 + 3/10 + 1/10

10 x 85 = 850

Step-by-step explanation:

2/5  wk 1 fall off

1/5  wk 2 fell off

3/5 x 1/2  = 3/10 wk 2 stayed on tree

1/3 x 3/10 = 1/10 wk 3 stayed on

2/5 + 1/5 + 3/10 = 9/10 =  0.9 fall off in total

10/10 - 9/10 = 1/10 left on tree

1/10 = 85

10 x 85 = 850 leaves.

8 0
3 years ago
Mei bought a box of markers for b dollars, a shoulder bag that cost twice as much as the box of markers and a pen that cost $6 l
Masteriza [31]
Box of markers = $ B

Shoulder bag =  Twice as much as the box of markers = $ 2B

Pen = Six less than the shoulder bag = $ (2B - 6)

Hence, the cost of pen is $ (2B - 6).
3 0
3 years ago
Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h​) <br>​
mel-nik [20]

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

7 0
3 years ago
Ok last question for today <br> Will mark brainliest
Pepsi [2]

Answer:9


Step-by-step explanation:

8 * 9 = 72

8, 16, 24, 32, 40, 48, 56, 64, 72

1, 2, 3, 4, 5, 6, 7, 8, 9

3 0
3 years ago
What is the solution for the determinant?
Liono4ka [1.6K]
<span>The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

The value of the determinant of a 2x2 matrix is the product of the top-left and bottom-right terms minus the product of the top-right and bottom-left terms.

= [ (1)(-3)] - [ (7)(0) ]
= -3 - 0
= -3

Therefore, the determinant is -3.

Hope this helps!</span>
4 0
3 years ago
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