Use the product to sum formulas to write the product as a sum or difference
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I found the missing parts of this question.
Test A
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>
<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>
<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>
Refer to the attachment for the formula of z score:
test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2
B. <span>Test A: –3; Test B: –2; Test B </span>
Test A
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>
<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>
<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>
Refer to the attachment for the formula of z score:
test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2
B. <span>Test A: –3; Test B: –2; Test B </span>