2 years ago

Simplify the square root of 50x^7y^10

1 answer:

7 0

$\sqrt{50x^{7}y^{10}} = \sqrt{50}* \sqrt{(x^{3})^{2}*x} * \sqrt{(y^{5})^{2}} =5 \sqrt{2}*x^{3} \sqrt{x} *y^{5}= \\ \\ 5x^{3}y^{5} \sqrt{2x}$

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Answer:

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Step-by-step explanation:

So, we need to first evaluate g(-3) and then plug the value of g(-3) into f(x) to find (fog)(-3). So, let's do that:

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Thus, (fog)(-3) = 125.

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Step-by-step explanation:

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Sunny_sXe [5.5K]

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