All categories

3 years ago

Simplify the square root of 50x^7y^10

1 answer:

7 0

$\sqrt{50x^{7}y^{10}} = \sqrt{50}* \sqrt{(x^{3})^{2}*x} * \sqrt{(y^{5})^{2}} =5 \sqrt{2}*x^{3} \sqrt{x} *y^{5}= \\ \\ 5x^{3}y^{5} \sqrt{2x}$

You might be interested in

What is the domain of f?

Sedbober [7]

The domain of a function is the set of all possible inputs for the function. For example, the domain of f(x)=x² is all real numbers, and the domain of g(x)=1/x is all real numbers except for x=0.

5 0

3 years ago

The graph below shows the design for the front view of a doghouse that Jeremy plans to build. If each square on the graph repres

dexar [7]

Based on the graph, the total perimeter of the doghouse Jeremy plans to build s 28 feet (twenty-eight feet).

<h3>What is the perimeter?</h3>

This is the total distance of all the sides in a shape. Due to this, the general formula is:

Perimeter = side + side + side.

<h3>What is the perimeter of the doghouse?</h3>

Horizontal side: 8 feet
Vertical sides: 10 feet
Diagonal sides: 10 feet

8+10+10= 28 feet.

Note: This question is incomplete because the graph is missing; here is the graph:

Learn more about perimeter in: brainly.com/question/6465134

#SPJ1

7 0

2 years ago

In the figure above, AB is tangent to the circle with center O

Radda [10]

<u>Given</u>:

Given that O is the center of the circle.

AB is tangent to the circle.

The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°

We need to determine the measure of ∠ABO.

<u>Measure of ∠ABO:</u>

The measure of ∠ABO can be determined using the triangle sum property.

Applying the property, we have;

$\angle ABO+\angle BAO+\angle AOB=180^{\circ}$

Substituting the values, we get;

$\angle ABO+90^{\circ}+68^{\circ}=180^{\circ}$

Adding the values, we have;

$\angle ABO+158^{\circ}=180^{\circ}$

Subtracting both sides by 158, we get;

$\angle ABO=22^{\circ}$

Thus, the measure of ∠ABO is 22°

6 0

3 years ago

What are the real zeros of x^3+4x^2-9x-36

Katyanochek1 [597]

Answer:

$x = -4\\x = -3\\x = 3$

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

$x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0$

Now we take (x + 4) as a common factor

$(x + 4)(x ^ 2 -9) = 0$

If we have an expression of the form $(a ^ 2-b ^ 2)$ we know that this expression is equivalent to:

$(a ^ 2-b ^ 2) = (a + b)(a-b)$

In this case

$a = x\\b = 3$

So:

$(x ^ 2 -9) = (x + 3)(x-3)$

Finally:

$x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0$

The solutions are:

$x = -4\\x = -3\\x = 3$

6 0

3 years ago

The perimeter of a right-angled triangle is 72 cm.

Verizon [17]

Answer:

the sides of the triangle are 4 cm , 8 cm , 20 cm

6 0

2 years ago