3 years ago

Simplify the square root of 50x^7y^10

1 answer:

7 0

$\sqrt{50x^{7}y^{10}} = \sqrt{50}* \sqrt{(x^{3})^{2}*x} * \sqrt{(y^{5})^{2}} =5 \sqrt{2}*x^{3} \sqrt{x} *y^{5}= \\ \\ 5x^{3}y^{5} \sqrt{2x}$

You might be interested in

forsale [732]

The answer is D. Ratio. When ever you see “per” another number it’s a ratio.

3 0

3 years ago

soldi70 [24.7K]

I believe the answer is 7

3 0

3 years ago

melomori [17]

D-median, because the presence of an outlier affect the data

5 0

3 years ago

DiKsa [7]

Answer:

-11°F

Step-by-step explanation:

The temperature was -4° in the morning. The temperature dropped 7° later.

Subtract 7 from -4.

$-4-7=\boxed{-11}$

The temperature should be -11°F.

Hope this helps.

6 0

3 years ago

kodGreya [7K]

$\text{Given that,}\\\\y^2 +9y +3 \\\\\text{when}~ y = -2,\\\\(-2)^2 +9(-2) +3 = 4-18+3 = 7 -18 = -11,$

8 0

2 years ago