Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
no solution
Step-by-step explanation:
6x - 3y = 7 → (1)
- 2x + y = - 8 → (2)
multiplying (2) by 3 and adding to (1) eliminates the variables
- 6x + 3y = - 24 → (3)
add (1) and (3) term by term
0 + 0 = - 17
0 = - 17 ← false statement
This indicates the system has no solution
Since the formula to find the area of a parallelogram is base times height (A=bh), and you have been given the area and base already, you can set up an equation. Let h=height in this formula. h x 3.4 = 25. Using this formula, to find the height, you would divide 25 by 3.4 and get approximately 7.35 inches. So, your height= 7.35in. Hope this helps!
(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
