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kykrilka [37]
2 years ago
9

Simplify the square root of 50x^7y^10

Mathematics
1 answer:
Alecsey [184]2 years ago
7 0
\sqrt{50x^{7}y^{10}} = \sqrt{50}* \sqrt{(x^{3})^{2}*x} * \sqrt{(y^{5})^{2}}  =5 \sqrt{2}*x^{3} \sqrt{x} *y^{5}= \\  \\ 5x^{3}y^{5} \sqrt{2x}
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6 0
2 years ago
A soccer team won 30% of their games and won 40 games. how many games did they play?
sweet [91]

Answer:

70

Step-by-step explanation:

i added 30% and 40

6 0
3 years ago
10. The community garden has 4
Lyrx [107]

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Read 2 more answers
Easy math, but not sure what I did wrong.
Ierofanga [76]

Answer:

8

Step-by-step explanation:

In his 5th year, he took 3 times as many exams as the first year.  So the number of exams taken in the 5th year must be a multiple of 3.

If a₁ = 1, then a₅ = 3.  However, this isn't possible because we need 4 integers between them, and a sum of 31.

If a₁ = 2, then a₅ = 6.  Same problem as before.

If a₁ = 3, then a₅ = 9.  This is a possible solution.

If a₁ = 4, then a₅ = 12.  If we assume a₂ = 5, a₃ = 6, and a₄ = 7, then the sum is 34, so this is not a possible solution.

Therefore, Alex took 3 exams in his first year and 9 exams in his fifth year.  So he took 19 exams total in his second, third, and fourth years.

3 < a₂ < a₃ < a₄ < 9

If a₂ = 4, then a₃ = 7 and a₄ = 8.

If a₂ = 5, then a₃ = 6 and a₄ = 8.

If a₂ = 6, then there's no solution.

So Alex must have taken 8 exams in his fourth year.

4 0
3 years ago
3(5-2x)=-4(cx+4)
ycow [4]

Answer:

c = 3/2

Step-by-step explanation:

hello :

3(5-2x)=-4(cx+4)

-6x+15 = - 4 cx-16

-6x+4cx = -16-15    means 6x-4cx=-31

(6-4c ) x = 31

the equation have no solutions when : 6-4c = 0   (you have : 0x=31...false)

-4c=-6

c= -6/-4

c = 3/2

7 0
3 years ago
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