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Alborosie
3 years ago
8

Please help

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0
The correct answer is <span>6x^4 −2x^3 + 26x^2 +x + 14.</span>
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Y=12x+6<br> y=12x+3<br> y=12x-3<br> y=12x-6
Natali [406]

Answer:

68

Step-by-step explanation:

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4 years ago
What's 7 * 49 in distributive property
Varvara68 [4.7K]

7 \times (7 + 42) \\  \\ 7 \times 7 + 7  \times 42 \\  \\  = 343
4 0
3 years ago
Which of the following relations represents a function?
sdas [7]

Answer:

Alternative D is correct

Step-by-step explanation:

For a relation to qualify as a function, a unique x value should be mapped to a unique y-value or unique x-values be mapped to the same y-value

4 0
3 years ago
Read 2 more answers
Calvin took his friends to a movie for his birthday the movie ticket cost 12 per person he spent less than 180
jarptica [38.1K]

180/12 = 15

 so if he spent less than 180 at most 14 people, including himself went.

4 0
4 years ago
The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm.
Akimi4 [234]

Answer:

Error in the sphere's surface: 29 cm^2  and relative error in surface measure: 0.011

Error in the sphere's volume: 205 cm^3 and relative error in the volume measure: 0.017

Step-by-step explanation:

(a)

The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:

l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm

and with regards to the error:

dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm

then when we use the formula for the sphere's surface, we get:

S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2

Then the relative error in the surface is:

\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011

(b)

Use the formula for the volume of the sphere:

V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3

Then the relative error in the volume is:

\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017

3 0
3 years ago
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