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MArishka [77]
3 years ago
13

How do i break apart to subtract 13 - 5

Mathematics
2 answers:
Anni [7]3 years ago
8 0
10+3-5=8

That would be how to break it apart
aleksklad [387]3 years ago
4 0
10+3-5=8
that is what it is broken apart
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It will be x multiplied to square root x.
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What’s the correct answer
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The correct answer might be A
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Please need help in these 3 algebra questions !!!!
Marysya12 [62]

Answer:

\large\boxed{7.\ B.\ 8s^2+16s+1}\\\\\boxed{8.\ D.\ -15t^9u^{11}}\\\\\boxed{11.\ C.\ 3,\ -2}

Step-by-step explanation:

7.\\(3s^2+7s+2)+(5s^2+9s-1)=3s^2+7s+2+5s^2+9s-1\\\\\text{combine like terms}\\\\=(3s^2+5s^2)+(7s+9s)+(2-1)\\\\=8s^2+16s+1

8.\\(-3t^2u^3)(5t^7u^8)=(-3\cdot5)(t^2t^7)(u^3u^8)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=-15t^{2+7}u^{3+8}=-15t^9u^{11}

11.\\n-the\ number\\\\n^2=n+6\qquad\text{subtract}\ n\ \text{and}\ 6\ \text{from both sides}\\\\n^2-n-6=0\\\\n^2+2n-3n-6=0\\\\n(n+2)-3(n+2)=0\\\\(n+2)(n-3)=0\iff n+2=0\ \vee\ n-3=0\\\\n+2=0\qquad\text{subtract 2 from both sides}\\n=-2\\\\n-3=0\qquad\text{add 3 to both sides}\\n=3

4 0
4 years ago
Un boligrafo cuesta 30 ptas mas que un lapiz. Un muchacho ha comprado 8 boligrafos y 15 lapices. En total le han costado 700 pta
Firdavs [7]

Por un sistema de ecuaciones, tiene-se que:

  • Cada lapiz cuesta 20 ptas.
  • Cada boligrafo cuesta 50 ptas.

-------------------------

  • Considera-se un sistema de ecuaciones, con cada boligrafo custando x y cada lapiz custando y.
  • <u>Boligrafo cuesta 30 mas que un lapiz</u>, o sea, x = 30 + y
  • <u>8 boligrafos y 15 lapices cuesta 700</u>, o sea, 8x + 15y = 700

-------------------------

  • Aplicando el <u>primer ecuación en la segunda, </u>tiene-se el cuesto de cada lapiz:

8x + 15y = 700

8(30 + y) + 15y = 700

240 + 8y + 15y = 700

23y = 460

y = \frac{460}{23}

y = 20

Cada lapiz cuesta 20 ptas.

-------------------------

Por fin, el cuesto de cada boligrafo es dado por:

x = 30 + y = 30 + 20 = 50

Cada boligrafo cuesta 50 ptas.

Un problema similar es dado en brainly.com/question/24637096

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Angle 5 is 39 degrees
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