Answer:
700
Step-by-step explanation:
to find the range, you subtract the smaller number of the two numbers from the larger one. If there is more than two numbers, you subtract the smallest one of the group from the largest one in the group. In this situation, you do 750-50, which is 700.
Answer:
8 x 12 = 96!
Step-by-step explanation:
It is the same as 8 x 12, which would have the answer of 96.
Answer:
Step-by-step explanation:
4x10=40
7x10=70
6x10=60
10x10=100
8x10=80
4x14=56
5x16=80
40+70+60+100+80+56+80= $486
Answer:
Part A:
-Minimum: 10
-Q1: 17.5
-Median: 30
-Q3: 42.5
-Maximum: 50
Step-by-step explanation:
Part B: IQR= 25
This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.
Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.
Answer:
P(X>17) = 0.979
Step-by-step explanation:
Probability that a camera is defective, p = 3% = 3/100 = 0.03
20 cameras were randomly selected.i.e sample size, n = 20
Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97
Probability that more than 17 cameras are working P ( X > 17)
This is a binomial distribution P(X = r) 
P(X>17) = P(X=18) + P(X=19) + P(X=20)
P(X=18) = 
P(X=18) = 
P(X=18) = 0.0988
P(X=19) = 
P(X=19) = 
P(X=19) = 0.3364
P(X=20) = 
P(X=20) = 
P(X=20) = 0.5438
P(X>17) = 0.0988 + 0.3364 + 0.5438
P(X>17) = 0.979
The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch
