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Zina [86]
3 years ago
5

A motorboat takes 5 hours to travel 150 miles going upstream. The return trip takes 3 hours going downstream. What is the rate o

f the boat in still water and what is the rate of the current?
Rate of the boat in still water:

Rate of the current:
Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

The rate of the boat in still water is 40 miles per hour

The rate of the current is 10 miles per hour

Step-by-step explanation:

we know that        

The speed or rate is equal to divide the distance by the time

Let

x ----> the rate of the current (miles per hour)          

y ----> the rate of the boat in still water (miles per hour)        

we have that          

<em>going upstream              </em>

y-x=\frac{150}{5}        

y-x=30 ----> equation A            

<em>going downstream                                  </em>

y+x=\frac{150}{3}                            

y+x=50 ----> equation B                            

Solve the system of equations by elimination                            

Adds equation A and equation B                                      

y-x=30\\y+x=50\\------\\y+y=30+50\\2y=80\\y=40                    

<em>Find the value of x                                </em>

y+x=50                

40+x=50            

x=10          

therefore          

The rate of the boat in still water is 40 miles per hour      

The rate of the current is 10 miles per hour      

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<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

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<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

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i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

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Hence, we get:

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Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

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