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ivolga24 [154]
2 years ago
7

The speed of a runner increased steadily during the first two seconds of a race. Col1 Time (Sec) 0 0.5 1 1.5 2 Col2 Speed (ft/se

c) 0 5.1 9.3 12.5 15.6 Estimate the distance she traveled during these two seconds using the speed at the end of the time intervals.A. 26.9B. 42.5C. 61.8D. 21.25E. 13.45
Mathematics
1 answer:
UkoKoshka [18]2 years ago
7 0

Answer:

The distance is D. 21.25 ft.

Step-by-step explanation:

This is an example of a distance problem: <em>Find the distance traveled by an object during certain time period if the velocity of the object is known at all times.</em>

We are given a table of values for time and speed

\left\begin{array}{cccccc}t(sec)&0&0.5&1&1.5&2\\Speed (ft/sec)&0&5.1&9.3&12.5&15.6\end{array}\right

If the speed remains constant, then the distance problem is easy to solve by means of the formula

                                          distance = speed x time

Therefore, the total distance is

distance = 5.1\cdot 0.5+9.3\cdot 0.5+12.5\cdot 0.5+15.6\cdot 0.5\\distance = 21.25 \:ft

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Answer:

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13.

The values for y are decreasing by 2 then drop by 12 from -2/14 to 0/-2 then increase again at a rate of 20 and decrease slightly to 18 being  -2/-20

we can see this as -2/16 ,-2/14 , 0/-2  2/ -22 meaning the line of symmetry is not clear as we cannot see an average without working out the mean or adding all the totals up.

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The value for p(4) is same method divide smaller into larger then times x 4

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