Question

The speed of a runner increased steadily during the first two seconds of a race. Col1 Time (Sec) 0 0.5 1 1.5 2 Col2 Speed (ft/sec) 0 5.1 9.3 12.5 15.6 Estimate the distance she traveled during these two seconds using the speed at the end of the time intervals.A. 26.9B. 42.5C. 61.8D. 21.25E. 13.45

Answer 1

Answer:

The distance is D. 21.25 ft.

Step-by-step explanation:

This is an example of a distance problem: Find the distance traveled by an object during certain time period if the velocity of the object is known at all times.

We are given a table of values for time and speed

$\left\begin{array}{cccccc}t(sec)&0&0.5&1&1.5&2\\Speed (ft/sec)&0&5.1&9.3&12.5&15.6\end{array}\right$

If the speed remains constant, then the distance problem is easy to solve by means of the formula

                                          distance = speed x time

Therefore, the total distance is

$distance = 5.1\cdot 0.5+9.3\cdot 0.5+12.5\cdot 0.5+15.6\cdot 0.5\\distance = 21.25 \:ft$