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3 years ago

What are some good notes I can use to study for my algebra exam tomorrow?

Mathematics

2 answers:

mixer [17]3 years ago

8 0

Practice questions and how to solve each type of questions

zlopas [31]3 years ago

4 0

Answer:

all you need to do is look over your notes continue to partice as much as you can

Step-by-step explanation:

you got this

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Find the perimeter.

Scorpion4ik [409]

Answer:

7 1/3 inches

Step-by-step explanation:

2 (1 3/4 + 1 11/12)

9+11

3/4+11/12= -------------

20/12

=1 2/3+ 2

2(3 2/3)

= 7 1/3

7 0

2 years ago

Write 0.00052 in scientific notation.

Kamila [148]

10 over the power of negative 4

4 0

2 years ago

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

$\= x = 18.5$ , $\sigma = 5.15$

$15.505 < \mu < 21.495$

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago

Kedwin has $150 and wants to buy a new pair of headphones that cost $175 + 10% shipping he decides wait until the headphones guy

SOVA2 [1]

Answer:

23%

Step-by-step explanation:

175 x 0.23 = 40.25

175-40.25 = 134.75

134.75 x 10% shipping = 13.48

134.75+13.48=148.23

7 0

3 years ago

Sean paints 8/15 of a fence in 1 hour. He paints 3/10 of the fence less in the second hour. What fraction of the fence did he pa

a_sh-v [17]

Answer: $\frac{3}{10}$

Step-by-step explanation:

Given

Sean paints $\frac{8}{15}$ of a fence in 1 hour

Sean paints $\frac{3}{10}$ part less in the second hour

So, fraction he paints in the second hour = $\frac{8}{15}-\frac{3}{10}=\frac{16-9}{30}=\frac{7}{30}$

Paint in 2 hours = $\frac{8}{15}+\frac{7}{30}=\frac{16-7}{30}=\frac{9}{30}$

= $\frac{3}{10}$

No, he did not finish his job

7 0

3 years ago

What are some good notes I can use to study for my algebra exam tomorrow?​

What are some good notes I can use to study for my algebra exam tomorrow?