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3 years ago

14

annabella and alex traveled 392 miles in 7 hours. if they travel at the same rate, how long will it take then to travel 728 mile

s

2 answers:

Igoryamba3 years ago

6 0

392 divided by 7 = 56 so 728 divided by 56=13 hours.
so 13 hours is your answer.

Thepotemich [5.8K]3 years ago

4 0

1. 392/7= 56
2. 728/56= 13
it would take them 13 hours.

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Please answer this and will marked as brainlist

xeze [42]

<h3>Answer: 1</h3>

where x is nonzero

=======================================================

Explanation:

We'll use two rules here

(a^b)^c = a^(b*c) ... multiply exponents
a^b*a^c = a^(b+c) ... add exponents

------------------------------

The portion [ x^(a-b) ]^(a+b) would turn into x^[ (a-b)(a+b) ] after using the first rule shown above. That turns into x^(a^2 - b^2) after using the difference of squares rule.

Similarly, the second portion turns into x^(b^2-c^2) and the third part becomes x^(c^2-a^2)

-------------------------------

After applying rule 1 to each of the three pieces, we will have 3 bases of x with the exponents of (a^2-b^2), (b^2-c^2) and (c^2-a^2)

Add up those exponents (using rule 2 above) and we get

(a^2-b^2)+(b^2-c^2)+(c^2-a^2)

a^2-b^2+b^2-c^2+c^2-a^2

(a^2-a^2) + (-b^2+b^2) + (-c^2+c^2)

0a^2 + 0b^2 + 0c^2

0+0+0

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All three exponents add to 0. As long as x is nonzero, then x^0 = 1

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3 years ago

Find the diagonal of a square whose sides are of the given measure.<br><br> Given =

Contact [7]

Answer:

7 $\sqrt{42}$

Step-by-step explanation:

The diagonal is the hypotenuse of the right triangle with legs 7 $\sqrt{3}$

Use Pythagoras' identity to solve for the diagonal d

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

d² = (7 $\sqrt{3}$ )² + (7 $\sqrt{3}$ )²

= 147 + 147

= 294 ( take the square root of both sides )

d = $\sqrt{294}$ = 7 $\sqrt{42}$ ≈ 45.37 ( to 2 dec. places )

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3 years ago

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Novay_Z [31]

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REY [17]

Answer:

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3 years ago

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k0ka [10]

A line that is parallel to another has exactly the same slope as the other.

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