Question

Point A lies on the circle and has an x-coordinate of 1.

Answer 1

For anyone wondering, the correct answer is D. I just finished the test on edge and it was correct.

Answer 2

Answer:

$\sqrt{(0-y)^{2}+(0-1)^{2}}=2$

Step-by-step explanation:

we know that

In the circle of the figure the radius is equal to 2 units

The distance from the center of the circle (origin) to the point A must be same at the radius

so

Applying the formula's distance between two points

point A( 1,y) and point (0,0)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$2=\sqrt{(0-y)^{2}+(0-1)^{2}}$

rewrite

$\sqrt{(0-y)^{2}+(0-1)^{2}}=2$