Answer: G. 12.5, 7.5, 10
Step-by-step explanation:
To determine the lengths of metal that could be used to form the tight angle triangle, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
The hypotenuse is the longest side while the opposite and adjacent sides are the shorter side. Therefore,
F.
8² = 4² + 4²
64 = 16 + 16 = 32
A right angle triangle cannot be formed because they are not equal.
G.
12.5² = 7.5² + 10²
156.25 = 56.25 + 100 = 156.25
A right angle triangle can be formed because they are equal.
H.
23² = 11² + 9²
529 = 121 + 81 = 202
A right angle triangle cannot be formed because they are not equal.
J.
96² = 12.5² + 6²
9216 = 156.25 + 36 = 192.25
A right angle triangle cannot be formed because they are not equal.
Answer:
total = 0;
for (k = 0; k <= n; k++)
total += Math.pow(k,3);
Step-by-step explanation:
Here the variable total is declared and initialized with a value zero
Then a for loop is defined with a counter k whose initial value is set to zero then a condition for the loop is that the counter k does not exceed n k<=n and then within the loop a statement which add the cube of the counter k to the variable total and still assigns it to the variable total is defined
total += Math.pow(k,3);
What this program does is to obtain the sum of the cubes of k
Answer:
see below
Step-by-step explanation:
2.x<1, y=all real numbers
3. -1<=x<=3 -3<=y<=2
4. x= all real numbers, y>-2
5. 7<=x<5, 3<=y<1
6.x>-4, y>-1
Answer:
A: -19
B: The equation has two complex solutions.
Step-by-step explanation:
(A) Compare
... x² +5x +11 = 0
to the form
... ax² + bx + c = 0
and you see that a=1, b=5, c=11.
The discriminat (d) is computed as
... d = b²-4ac
Putting the above values in this equation for a, b, c, we get
... d = 5² -4·1·11 = 25 -44 = -19
_____
(B) The solutions are ...
... x = (-b ±√d)/(2a) = (-5 ±√-19)/2
The square root of -19 is imaginary, so there are two complex solutions. It will be the case that the two solutions are complex whenever the discriminant is negative.
